x^2+x-530=0

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Solution for x^2+x-530=0 equation:



x^2+x-530=0
a = 1; b = 1; c = -530;
Δ = b2-4ac
Δ = 12-4·1·(-530)
Δ = 2121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2121}}{2*1}=\frac{-1-\sqrt{2121}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2121}}{2*1}=\frac{-1+\sqrt{2121}}{2} $

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